High velocity interfacial collision: Is it a potential method to produce a nanoporous surface?

magnetic pulse forming and welding processes using numerical simulations T. Sapanathan1, K. Yang1,N. Buiron1 and M. Rachik1 1 Sorbonne universités, Université de technologie de Compiègne, CNRS, laboratoire Roberval [...] (seconds) Z= 0.0 mm_top edge Z= 0.5 mm from top edge Z= 1.0 mm from top edge Z= 1.5 mm from top edge Z= 2.0 mm from top edge 14 0.0E+00 5.0E+05 1.0E+06 1.5E+06 2.0E+06 2.5E+06 3.0E+06 0.0E+00 2.0E-06 4.0E-06 [...] 0E+04 1.0E+05 1.5E+05 2.0E+05 2.5E+05 3.0E+05 3.5E+05 4.0E+05 0.0E+00 1.0E-06 2.0E-06 3.0E-06 4.0E-06 5.0E-06 V e lo ci ty ( m m /s ) Time (Seconds) Z= 0.0 mm_top edge Z= 0.5 mm from top edge Z= 1.0 mm …

FEM simulation of thixo‐viscoplastic flow problems: Error analysis

2τ∞k + C1 |u|1 + C1 |v|1) ||u− v||1 ||η||1 + 2(η∞ |v|1 + τ∞) ||λ− ξ||1 ||η||1 (20) aλ(ũ)(λ, ζ)− aλ(ṽ)(ξ, ζ) ≤(Ma + (2C1 + C2Mb) |u|1) ||λ− ξ||0 ||ζ||1 + (2C1 + C2Mb) ||ξ||1 ||u− v||1 ||ζ||1 (21) Proposition [...] 4(2η∞ + 2τ∞k + C1 |vh|1 + C1 |u|1)2 (η0CK − C1 |uh|1)2 (39) Cu,λ(η0, η∞, τ∞, CK , |u|1) = 4(2η∞ |u|1 + τ∞)2 (η0CK − C1 |uh|1)2 (40) Cu,p(d, η0, CK) = 4( √ 2d)2 (η0CK − C1 |uh|1)2 (41) Then, ||ξh − λh||20 [...] ξh||0) |ηh|1 + τ∞ (2k |vh − u|1 + ||λ− ξh||0) |ηh|1 + (C1 |vh|1 + C1 |u|1) |vh − u|1 |ηh|1 (33) beside the continuity of b(·, ·) on right hand side of (29) b(ηh, p− ph) ≤ √ 2d ||p− ph||0 |ηh|1 , (34) to conclude …

Gründen Mitglied der Universität gemäß § 9 Abs. 1 S. 1 HG ist, nimmt er*sie an Wahlen gemäß § 9 Abs. 1 S. 4 HG nicht teil. (3) 1Die Bezeichnung wird in der Erwartung verliehen, dass der*die Honorarprofessor*in [...] Universität gemäß § 9 Abs. 1 S. 1 HG. 4Soweit er*sie nicht zugleich aus anderen Gründen Mitglied der Universität ist, nimmt er*sie gemäß § 9 Abs. 1 S. 4 HG nicht an Wahlen teil. (5) 1Die Verleihung der Bezeichnung [...] Bezeichnung „Professorin“ oder „Professor“ zu führen. (2) 1Durch die Verleihung wird der*die Honorarprofessor*in Mitglied der Universität gemäß § 9 Abs. 1 S. 1 HG. 2Soweit er*sie nicht zugleich aus anderen Gründen …

Microsoft Word - Prachayasittikul_270910_proof.doc

1013, 987 cm-1 , 1H-NMR (300 MHz, CDC13): δ = 1.55, 1.62, 1.82, 1.85, 2.07, (5s, 15H, 1-AdmH), 1.85 (s, 3H, NCOCH3), 2.33 (s, 3H, OCOCH3), 5.50-5.56 (m, 2H, H-3, H-6), 5.63 (d, J = 11.4 Hz, 1H, OH), 6.28 [...] supplied. 1-Adamantanethiol (1-AdmSH) was prepared by the literature method (Khullar and Bauer, 1971). Figure 1: Chemical structures of 1,2,3,4- and 1,2,3,6-tetrahydropyridines Synthesis of N-acetyl-2-(1-adamantyl- [...] J = 2.1 Hz, 1H, H-2), 6.35 (d, J = 3.0 Hz, 1H, H-5), 7.25 (s, 5H, PhH). 13C-NMR (75 MHz, CDC13) : δ = 20.8 (NCOCH3), 21.7 (OCOCH3), 29.3 (3 × CH-1-Adm), 35.0, 36.0 (6 × CH2-1-Adm), 57.8 (Cqua-1- Adm), …

Microsoft Word - Banerjee_13052011_proof-1.doc

17 8 +1 +1 +1 –1 –1 52.33 9 –1 –1 –1 +1 +1 61.33 10 +1 –1 –1 +1 +1 58.03 11 –1 +1 –1 +1 +1 54.91 12 +1 +1 –1 +1 –1 47.34 13 –1 –1 +1 +1 –1 82.58 14 +1 –1 +1 +1 –1 81.04 15 –1 +1 +1 +1 0 66.43 16 +1 0 +1 [...] order A1 A2 A3 A4 A5 Deligni- fication (%) 1 –1 –1 –1 –1 +1 82.34 2 +1 –1 –1 –1 –1 65.47 3 –1 +1 –1 –1 –1 44.23 4 +1 +1 –1 –1 +1 47.90 5 –1 –1 +1 –1 –1 81.67 6 +1 –1 +1 –1 +1 38.65 7 –1 +1 +1 –1 +1 39.17 [...] 54.50 3 –1 +1 –1 28.90 19.45 8.89 8.09 0.78 66.25 4 +1 +1 –1 50.60 23.09 14.56 9.34 0.57 98.50 5 –1 –1 +1 34.56 21.08 8.67 5.68 0.22 70.25 6 +1 –1 +1 32.40 20.30 8.67 4.45 0.81 66.78 7 –1 +1 +1 31.78 23 …

cpriorλ exp ( 1 2 e′λE −1 λ eλ − 1 2 β′0λΩβ0 ) exp { −1 2 (β − eλ)′E−1λ (β − eλ) } ISm(β) p(λ) λ r 2 |Eλ| 1 2 cpostλ cpriorλ exp ( 1 2 e′λE −1 λ eλ − 1 2 λβ′0Ωβ0 ) ∝ |Eλ|− 1 2 exp { −1 2 (β − eλ)′E−1λ (β − eλ) [...] |Ω̃| 1 2 cpriorλ exp ( 1 2 e′λE −1 λ eλ − 1 2 β′0Ω̃β0 ) exp { −1 2 (β − eλ)′E−1λ (β − eλ) } ISm(β) p(λ,m) |Ω̃| 12 |Eλ| 1 2 cpostλ cpriorλ exp ( 1 2 e′λE −1 λ eλ − 1 2 β′0Ω̃β0 ) ∝ |Eλ|− 1 2 exp { −1 2 (β [...] βj ≥ βj−1 ∀j = −k, . . . ,m and βj ≤ βj−1 7 ∀j = m+ 1, . . . , g. This can be written as the linear constraint A′mβ ≥ 0 with A′m =  −1 1 . . . . . . 0 −1 1 1 −1 0 . . . . . . 1 −1  …

sei der reine Zufall 50%. λ = 1/3, weil (1− 1/3) · Acc = 50%. Wegen Gleichung (2) ergibt sich: Pr [Âcc ≤ (1− 1/3) · Acc] ≤ exp(−(1/3)2m · Acc/2) ⇔ Pr [Âcc ≤ 1/2] ≤ exp(−1/9m3/8) = exp(−m 24 ) Risiko ≤ [...] sei der reine Zufall 50%. λ = 1/3, weil (1− 1/3) · Acc = 50%. Wegen Gleichung (2) ergibt sich: Pr [Âcc ≤ (1− 1/3) · Acc] ≤ exp(−(1/3)2m · Acc/2) ⇔ Pr [Âcc ≤ 1/2] ≤ exp(−1/9m3/8) = exp(−m 24 ) Risiko ≤ [...] sei der reine Zufall 50%. λ = 1/3, weil (1− 1/3) · Acc = 50%. Wegen Gleichung (2) ergibt sich: Pr [Âcc ≤ (1− 1/3) · Acc] ≤ exp(−(1/3)2m · Acc/2) ⇔ Pr [Âcc ≤ 1/2] ≤ exp(−1/9m3/8) = exp(−m 24 ) Risiko ≤ …

|G| ] ≤ E [ opt + ∑opt i=1 3Xi ] ≤ opt + ∑opt i=1 3E [Xi] ≤ opt + ∑opt i=1 3 4 ∆ = (1 + 12 ∆ )opt = (1 + ε)opt Shifting Quadtrees in 1 dimension Given point set P of n points in [ 1 2 , 3 4 ] . Draw b ∈ [ [...] ≤ 4 2t b + 0 b + 1α β level 0 −1 −2 −3 Lb(α,β) = −1 Shifting Quadtrees in 1 dimension Given point set P of n points in [ 1 2 , 3 4 ] . Draw b ∈ [ 0, 12 ] uniformly at random. Consider 1-dim Quadtree T on [...] Lb(α,β) > log2 |α− β| + t ] ≤ ∑∞ i=1+t P [ Lb(α,β) = M + i ] ≤ ∑∞ i=t P [XM+i = 1] ≤ ∑∞ i=t |α−β| ∆M+i ≤ ∑∞ i=t 2 1−i ≤ 22−t b + 0 b + 1α β level 0 −1 −2 −3 Let XM+i = 1Iα,β in different intervals. If Lb(α …